what you are asking is [tex]4 \frac{1}{3} -2 \frac{3}{4} [/tex] we need to make the fractions improper now, [tex] \frac{13}{3} - \frac{11}{4} [/tex] now we need common denominators: [tex] \frac{52}{12} - \frac{33}{12} [/tex] we get [tex] \frac{19}{12} [/tex] OR [tex]1 \frac{7}{12} [/tex]
