Find the area of each parallelogram plz help

Answer: The area of the parallelogram is:
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[tex] \frac{9393}{8} [/tex] in² = 1174 ⅛ in² = 1174.125 in² .
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Explanation:
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Area of a parallelogram:
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A = base * height = b * h ;

From the figure (from the actual "question"):
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b = 50.5 in.

h = 23.25 in.
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Method 1) A = b * h =

= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 ⅛ .
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Method 2) A = b * h =

= (50 ½ in) * (23 ¼ in) =

= ([tex] \frac{101}{2} [/tex] in) * ([tex] \frac{93}{4} [/tex] in) ;
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Note: "50 ½ " = [(50*2) + 1 ] / 2 = [tex] \frac{101}{2} [/tex] ;

Note: "23 ¼ " = [(23*4) + 1 ] / 4 = [tex] \frac{93}{4} [/tex] ;
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→ A = ([tex] \frac{101}{2} [/tex] in) * ([tex] \frac{93}{4} [/tex] in) ;

→ A = [tex] \frac{(101*93)}{(2*4)} [/tex] in² = [tex] \frac{9393}{8} [/tex] in² ;

→ A = (9393/8) in² =

→ A = [tex] \frac{9393}{8} [/tex] in² = 1174 ⅛ in² = 1174.125 in² .
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