Respuesta :

[tex]\begin{gathered} 7x-2x+3\mleft(x+2\mright)=4x-2\mleft(x-2\mright)​ \\ 7x-2x+3x+6=4x-2x+4​ \\ 8x+6=2x+4 \\ 8x-2x=4-6 \\ 6x=-2 \\ \frac{6x}{6}=\frac{-2}{6} \\ x=-\frac{2}{6}=-\frac{1}{3} \end{gathered}[/tex]

There is only one solution to these equations

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