Given resistance in ohms and current in ampere, the power can be calculated by the equation, P = I² x R where I is current, P is power, and R is resistance Substituting the given values, 1.00 x 10² = (I²) x 136 ohms ; I = 0.8575 amp Then, by Ohm's law, the value of V = I x R. Substituting, V = (0.8575 amp) x (136 ohms) = 116.619 volts Thus, the potential difference across the lamp is approximately equal to 116.619 volts.
