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A 0.10 kg stone is thrown from the edge of an ocean cliff with an initial speed
of 20 m/s. When it strikes the water below, it is traveling at 45 m/s. What is the
change in the kinetic energy of the stone?

Respuesta :

27sarahwill

Answer:

79.20 joule

Explanation:

1.

A 0.10kg stone is thrown from the edge of an ocean cliff with an initial speed of 21m/s. When it strikes the water below, it is traveling at 45m/s. What is the change in kinetic energy of the stone?

Ī”Ek = m/2*(V2^2-V1^2) = 0.05*(45^2-21^2) = 79.20 joule

onyebuchinnaji

The change in the kinetic energy of the stone is 81.25 J.

The given parameters;

  • mass of the stone, m = 0.1 kg
  • initial speed of stone, u = 20 m/s
  • final velocity of the stone, v = 45 m/s

The initial kinetic energy of the stone is calculated as follows;

K.E = Ā¹/ā‚‚muĀ²

K.Eā‚ = Ā¹/ā‚‚ x 0.1 x 20Ā²

K.Eā‚ = 20 J

The final kinetic energy of the stone is calculated as follows;

K.Eā‚‚ = Ā¹/ā‚‚ x 0.1 x 45Ā²

K.Eā‚‚ = 101.25 J

The change in the kinetic energy of the stone is calculated as follows;

Ī”K.E = K.Eā‚‚ - K.Eā‚

Ī”K.E = 101.25 J Ā - Ā 20 J

Ī”K.E = 81.25 J

Thus, the change in the kinetic energy of the stone is 81.25 J.

Learn more here:https://brainly.com/question/15598542

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